Loading... Please wait...This very tall (6.5"/153mm) 7-segment display can be seen from a hundred feet away.
Documents: Datasheet
This Shifter Board drives these displays nicely!
Posted by Phil on 7th May 2013
Hi, here is a project I am working on, I am driving the display directly with TPIC6B595 high-powered shift registers and 47ohm series resistors from a 13.8V supply. Average current drawn by the whole display is just over 0.5A. The brightness of the display is pretty good and readable in all but direct sunlight.
http://www.youtube.com/watch?v=XdteNh2kWEM&feature=youtu.be
Posted by Unknown on 25th Apr 2013
7-SEGMENT EXAMPLE USING PIC18F4520
http://pic18forstudents.co.uk/
Posted by Unknown on 22nd Aug 2012
Thank you for your explanation.
We do actually get a dimming, and also some odd cross-talk when using your shifters and circuit. The segments which are meant to be off are often lit dimly. I don't see the same problem on your video, but it does look like you're using different value pullup resistors (10k instead of 1k), but that could be a trick of the camera.
If I get time to do more work on this circuit, I'll be sure to send back my findings.
Thanks for your responses!
Posted by Richard - Proto-PIC on 22nd Aug 2012
Ah, now i understand you. These are pull up resistors, so that the cathodes are pulled up to 12V to switch off, then driven low by the shift resistor.
If you need constant brightness across each segment you could be individual limiting resistors in between the the shifter and the cathode of each segment, but we didnt really notice a big difference when we were prototyping and so opted for the 1 resistor.
Posted by Unknown on 22nd Aug 2012
I was referring to the fact that you do not use a resistor in series with EACH segment, but instead use a single 47 Ohm one shared among all segments.
This means that when a single segment is lit, then others are lit, the first one dims as the current is shared out between all of the active segments.
The circuit suggested on the shifter datasheet doesn't quite make sense to me, as the resistors I had originally assumed to be per-segment are actually pulling the cathode of the segments up to 12v instead. Is there a simple reason for these resistors?
Posted by Richard - Proto-PIC on 13th Aug 2012
The current limiting resistor is there to protect the LED segment from blowing.
Without the Resistor the LED is free to take any current the supply can give it, the resistor is there to stop this from happening.
You need 20mA for a nice brightness.
We used 47ohm resistors on a 12V supply.
Its bad practise to light an LED from a supply without a resistor in there to limit the current. You might "get away with it" in certain situations where you are using a CR2032 coin cell as the supply. But if your supply has the ability to supply more current than the LED needs - you have to limit it
Posted by Unknown on 13th Aug 2012
Just to be clear, that means there's a few LEDs in each segment. The voltage drop is sufficient to mean that if you're supplying 12v, you don't need to limit the current with a resistor in series with each segment.
Is that an accurate summary?
Posted by Roy on 6th Aug 2012
The voltage drop across each LED segment is just under 12V
Posted by Unknown on 6th Aug 2012
Hi,
What's the voltage drop for each LED in the display? The datasheet does not avail us of these details.
Cheers